x^2+50x-12=0

Solution for x^2+50x-12=0 equation:

x^2+50x-12=0

a = 1; b = 50; c = -12;
Δ = b2-4ac
Δ = 502-4·1·(-12)
Δ = 2548
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2548}=\sqrt{196*13}=\sqrt{196}*\sqrt{13}=14\sqrt{13}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-14\sqrt{13}}{2*1}=\frac{-50-14\sqrt{13}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+14\sqrt{13}}{2*1}=\frac{-50+14\sqrt{13}}{2}
$